From the information the mean and standard deviation of random variable m p: =25 and 0:5. The value of the observation that exceeds 85% of time is calculated as follows: P(X>x)=0.85 =>P[X_'\" > x_25]=0_85 a 5 :>P[X"" x=251.0364(5) => x=19-82 Thus, the value i~x= 19.8