\fStep 1 - - 5x 7 x22 given equation 2(6 ) x 2 2f \"(6 ) taking log of the above expression, X X log5 log (2V5) : (X2 2)log (6) 0.699X 0.650 : (x2 2)0.778 0.7'78X2 1.556 + 0.650 0.699X : 0 0.7780:2 0.69934: 0.906 : 0 Explanation Please refer to solution in this step. Step 2 solving the above quadratic equation, 0.699 + (0.099)2 4 x 0.778 X (0.900) X1 : 2 X 0.778 : 1.618 0.099 (0.099)2 4 x 0.778 x (0.906) X2 : 2 x 0.778 : 0.720