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F(t) = e == [e- dr exists, but what is its exact value? To find it, we introduce the functions and r1 e-t (x+1)
F(t) = e == [e- dr exists, but what is its exact value? To find it, we introduce the functions and r1 e-t (x+1) G(t) = dx x+1 H(t) = F(t)+G(t). (e) Compute and simplify H'(t). What does that tell you about H(t)? Hint: At some point, you might want to do the substitution y = tx.
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