\fThe accompanying table contains the ratings of 9 different TV and Internet sen/ice providers. How do the ratings of TV and Internet services compare? Complete parts (a) through (d). Click the icon to view the data table. a. At the 0.05 level of significance. is there evidence of a difference in the mean service rating between TV and Internet services? Let PD be the mean of the population of differences TV service rating minus Internet service rating. What are the null and alternative hypotheses? 3A. H0:pD20and H12|.LD0 The test statistic is tSTAT = 5.53 . (Type an integer ora decimal. Round to two decimal places as needed.) The pvalue is 0.001 . (Type an integer ora decimal. Round to three decimal places as needed.) Since the p-value is less than the level of signicance. reject the null hypothesis. There is sufficient evidence to conclude there is a difference in the mean service ratings. b. What assumption is necessary in order to perform this test? it A. It is assumed that the distribution of the differences is approximately uniform. - B. It is assumed that the distribution of the differences is approximately normal. '3 c. It is assumed that the samples are paired. c. Use a graphical method to evaluate the validity of the assumption in (a). Construct a boxplot of the differences. Choose the correct graph below. O A. OB. O c. OD. - T HI 5 5 0 5 5 5 Difference Difference Difference Difference Does the assumption needed in order to conduct the t test in (a) appear to be valid? because the boxplot indicates the distribution of the differences is d. Construct and interpret a 95% confidence interval estimate of the difference in the mean service rating between TV and Internet services. SHD S (Type integers or decimals. Round to two decimal places as needed.) Interpret this interval. With 95% confidence, the interval contains the the service ratings for TV and Internet services