g [[3 FigureSkatersand Baseball Bats x Solutrunrorusersrequesi. x l :19 Course: Fall Semester20237CL; x l u Dashboard x | + 6 G \\El https://ugf.mroom53.net/mod/quiz/altempt.phpEattempt:355050&cmid:694244 A\" {'3 g a 711% Q a {3 [D {'5 0Q AdsManagerrMa\" [j "Smalldlsclpllnesre. 1 VitalSource Booksh.. Course ScheduleVl\" E Welcometo ZapierL E [mauliheckerrvu ShillerPE Ratio "/1 Wilshlre 5000 Total... ' FolorPholo Editor\" incomplete answer Marked out ofSDD \\2 Flag question 5\" Sunny In the theory of collisions we find that conservation of momentum can imply a loss of kinetic energy in the system of colliding objects. This is what happens for an inelastic collision. There is an analogous phenomenon in rotational motion of a single body whereby the fundamental principle of conservation of angular momentum can imply a gain or loss of rotational kinetic energy. You will calculate the gain in one model scenario here. Suppose a figure skater is initially spinning with her arms spread out wide, having a moment of inertia I0 = 2.7 kg m2 and constant angular velocity wt) 2 6 radians per second. (Roughly one revolution per second.) Then she folds her arms in tightly to her body, reducing her moment of inertia to If 2 1.5 kg m2. Use the fact that angular momentum L 2 [cu is conserved through this change to compute the new angular velocity, wf radians per second, that she will be spinning with after folding her arms in. Answer: You must enter a valid number. Do not include a unit in your response. Q Search 7 D X 9 \"'o i, ['1 Other favorites 11:25 AM 10/2/2023 A Figure Skaters and Baseball Bats X * Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA x + X C @ https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244 X b Ads Manager - Ma.. "Small disciplines re... VitalSource Booksh... D2L Course Schedule - 1... _ Welcome to Zapier!... E Email Checker - Ver... m Shiller PE Ratio Wilshire 5000 Total.. Fotor Photo Editor-... Other favorites UNIVERSITY OF PROVIDENCE DD My Courses response. Question 2 Incomplete answer Marked out of 1.00 P Flag question For the same figure skater, find the initial rotational kinetic energy (in Joules) that she had while spinning with her arms outstretched. Answer: You must enter a valid number. Do not include a unit in your response. Question 3 Answer saved Marked out of 1.00 P Flag question 58.F Sunny Q Search 11:25 AM 10/2/2023Figure Skaters and Baseball Bats X * Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA X + X C https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244 X S b Ads Manager - Ma... "Small disciplines re... VitalSource Booksh.. D21 Course Schedule - 1.. _ Welcome to Zapier!... E Email Checker - Ver... m Shiller PE Ratio Wilshire 5000 Total.. Fotor Photo Editor-.. Other favorites Question 3 Answer saved Marked out of 1.00 Flag question Lastly, calculate the final rotational kinetic energy of the figure skater (in Joules) after she has pulled her arms in. (You should find that the kinetic energy has increased, because in the formula K = - Iw the increase in angular velocity more than compensates for the decrease in moment of inertia. As a follow up note, you may wish to compare the ratio of initial to final kinetic energy to the ratio of final to initial moment of inertia. There is a noteworthy correspondence there.) Answer: Next page Quiz navigation 58.F 1X O 11:26 AM Sunny Q Search 10/2/2023Figure Skaters and Baseball Bats X Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA x + X C https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244&page=1 X S b Ads Manager - Ma... "Small disciplines re... VitalSource Booksh... D21 Course Schedule - I... _ Welcome to Zapier!... E Email Checker - Ver... m Shiller PE Ratio Wilshire 5000 Total... Fotor Photo Editor-.. Other favorites UNIVERSITY OF PROVIDENCE DD My Courses Question 4 Not yet answered Marked out of 4.00 P Flag question Consider a simple "baseball bat" that is in the shape of a single cylinder of radius 3 cm and length 1 meter. To obtain the mass of the bat, we'll assume that it is a good dense oak wood with a mass density of 750 kg per cubic meter. Find the volume of the cylinder (in cubic meters) and multiply by this mass density to obtain the total mass of the bat. Finding the mass of the bat is a preparatory step for the real question: to find the moment of inertia I of this bat around an axis at one end. Use the chart of moments of inertia from the textbook together with the parallel axis theorem to determine the moment of inertia (in kg m) about an axis at one end of the bat. (The official answer will use the formula for cylinders, not the "thin rod" approximations that pretend the radius of the cylinder is 0.) Enter your calculated moment of inertia below, in units of kg m2. Answer: Waiting for ugf.mrooms3.net... 58.F Sunny Q Search 11:26 AM 10/2/2023Figure Skaters and Baseball Bats X * Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA x + X C https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244&page=1 X S b Ads Manager - Ma... "Small disciplines re... VitalSource Booksh... D21 Course Schedule - I... _ Welcome to Zapier!.. .. E Email Checker - Ver. m Shiller PE Ratio Wilshire 5000 Total... Fotor Photo Editor-... Other favorites Question 5 Not yet answered Marked out of 4.00 P Flag question Now consider a more sophisticated bat, intended to push the mass further out from the axis of rotation at the end. The bat is made of the same good oak wood, and is still 1 meter in overall length, but now the first half of its length is a thin cylinder of radius 2 cm and the second half of it's length is a thicker cylinder of radius 3.75 cm. As a preparatory step for this problem, you'll have to find the mass of each of the two cylindrical halves of the bat separately. Once you have the mass of the thin "handle" end of the bat, use the parallel axis theorem and moment of inertia chart to find the moment of inertia of the thinner "handle" half of the bat about an axis perpendicular to the handle end. Answer: 58.F 11:26 AM Sunny Q Search 1X O 10/2/2023Figure Skaters and Baseball Bats X * Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA x + X C https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244&page=1 X b Ads Manager - Ma... "Small disciplines re... VitalSource Booksh... D21 Course Schedule - 1.. _ Welcome to Zapier!.. .. E Email Checker - Ver.. m Shiller PE Ratio Wilshire 5000 Total.. Fotor Photo Editor-... Other favorites UNIVERSITY OF PROVIDENCE swer: DD My Courses Question 6 Not yet answered Marked out of 4.00 | Flag question Now find the moment of inertia of the thicker "business half" of the bat about the axis perpendicular to the handle end of the bat. Follow the same procedure as before - first calculate the mass, then use the moment of inertia table with the parallel axis theorem. Answer: 58.F 11:26 AM Sunny Q Search 1X O 10/2/2023P Figure Skaters and Baseball Bats X * Homework Help - Q&A from Onl X Solution for user's request. X Course: Fall Semester 2023 - CLA x + X C @ https://ugf.mrooms3.net/mod/quiz/attempt.php?attempt=355050&cmid=694244&page=1 X b Ads Manager - Ma... "Small disciplines re... VitalSource Booksh... D21 Course Schedule - I.. _ Welcome to Zapier!... .. E Email Checker - Ver. m Shiller PE Ratio Wilshire 5000 Total... Fotor Photo Editor-.. Other favorites Not yet answered Marked out of 1.00 P Flag question Now suppose both bats are swung at angular velocity w = 15 radians per second about an axis perpendicular to the handle end. Compute the rotational kinetic energy of the first (simple cylinder) bat. Answer in Joules. Answer: Question 8 Not yet answered Marked out of 2.00 | Flag question Finally, find the kinetic energy of the improved bat (thinner cylinder at handle side, thicker cylinder at business end). Answer: 58.F 11:26 AM Sunny Q Search 10/2/2023