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GENERAL PHYSICS 2 Please answer Activities 1-3 given after the references provided below. Please provide the best and original answers with effective solutions. Some answers
GENERAL PHYSICS 2
Please answer Activities 1-3 given after the references provided below. Please provide the best and original answers with effective solutions. Some answers are provided in some activities but it requires the right solutions.
Please read the provided references to be able to answer the activities and read the instructions and questions in every activity.
Thank you so much ,Tutors!!
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Activity 1 Problem Solving (Answer without solution will not be considered) A positron is a type of antimatter that is just like an electron collides with an electron, their masses are completely annihilated (combined) and converted to energy in the form of gamma rays. (both particles have a rest mass of 9.11 x 10- 31 kg. Determine the energy produce. Hint: The mass of positron and electron combined during collision, therefore m(positron + electron) Speed of light (3.0 x 10 m/s)Activity 2 Problem Solving (Answer without solution will not be considered) The Speed of Light. One night you are out looking up at the stars and an extra- terrestrial spaceship flashes across the sky. The ship is 50 meters long and is travelling at 95 percent of the speed of light. What would the ship's length be when measured from your earthbound frame of reference? Activity 3 Problem Solving (Answer without solution will not be considered) Leo and Christian are twins. At the age of 30, Leo left for a round trip to a distance star in a spaceship with a speed of 0.95c relative to Earth. The whole trip took 20 years according to the shipboard clock. Find the ages when Leo returns (answer: Leo would be 50 years old, while his twin brother Christian would be 94 years old) Check this out: . https://openstax.org/books/physics/pages/10-2-consequences-of-special- relativityLearning Competencies: - State the postulates of Special Relativity and their consequences STEM_GP12MP- Dig-39 - Apply the time dilation and length contraction formulae ST EM_GP12MP-IVg-4D - Calculate kinetic energy, rest energy, momentum, and speed of objects moving with speeds comparable to the speed of light ST EM_GP12MP-IVg-42 Subject Matter: Systecialr Relativity, Fine Dilation, Length Contraction, Momentum, Speed of Objects Points to Ponder . Time dilation has been conrmed by comparing the time recorded by an atomic clock sent into orbit to the time recorded by a clock that remained on Earth. GPS satellites must also be adjusted to compensate for time dilation in order to give accurate positioning. - Have you ever driven on a road, like that shown below, that seems like it goes on forever? If you look ahead, you might say you have about 10 km left to go. Another traveler might say the road ahead looks like it is about 15 km long. If you both measured the road, however, you would agree. Traveling at everyday speeds, the distance you both measure would be the same. You will read in this section, however, that this is not true at relativistic dinerentiy; but at reiativistic speeds. Close to the speed of light, speeds the distances really are distances measured are not the same o'ierent. when measured by different observers moving with respect to one other. a One thing all observers agree upon is their relative speed. When one observer is traveling away from another, they both see the other receding at the same speed, regardless of whose frame of reference is chosen. Remember that speed equals distance divided by time: 1/ = d/t. If the observers experience a difference in elapsed time, they must also observe a difference in distance traversed. This is because the ratio 0% must be the same for both observers. Peopie might describe distances . The shortening of distance experienced by an observer moving with respect to the points whose distance apart is measured is called length contraction. Proper length, Lo, is the distance between two points measured in the reference frame where the observer and the points are at rest. The observer in motion with respect to the points measures 1.. These two lengths are related by the equation Relativistic momentum is conserved, and much of what we know about subatomic structure comes from the analysis of collisions of accelerator-produced relativistic particles. One of the postulates of special relativity states that the laws of physics are the same in all inertial frames. Does the law of conservation of momentum survive this requirement at high velocities? The answer is yes, provided that the momentum is dened as follows. Where: 3.) Relativistic momentum at mass of the object (mass measured at rest, without any y factor involve cl), u velocity relative to an observer, 1: relativistic factor Note that we use 1:. for velocity here to distinguish it from relative velocity v between observers. Only one observer is being considered here. With p dened in this way, pm,\" is conserved whenever the net external force is zero, just as in classical physics. Again we see that the relativistic quantity becomes virtually the same as the classical at low velocities. That is, relativistic momentum ymu becomes the classical mu at low velocities, because 1: is very nearly equal to 1 at low velocities. Mass-Energy Equivalence 1 . where v and care as dened earlier. We use I: as the 1,2 velocity of a particie or an object in one frame of 132" reference, andvfor the velocity of one frame of reference with respect to another. "F: nre Dilation . Eiapsed time on a moving object, arm as seen by a stationary observer - where an, is the time observed on the moving object when it is taken to be the frame or reference. At = ytto Length Contraction L . Length measured by a person at rest with respect to a L = moving object, L y where Lu is the length measured on the moving object. Reiatfvistfc Energy . The rst postulate of relativity states that the laws of physics are the same in all inertial frames. Einstein showed that the law of conservation of energy is valid relativistically, if we dene energy to include a relativistic factor. The result of his analysis is that a particle or object of mass m moving at velocity u has relativistic energy given by E = 3!ch . This is the expression for the total energy of an object of mass mat any speed u and includes both kinetic and potential energy. Look back at the equation for y and you will see that it is equal to 1 when u is 0;. that is, when an object is at rest. Then the rest energy, E", is simply 0 = mt:2 . This is the correct form of Einstein's famous equationStep by Step Solution
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