General Physics

Resistors in series

1. Calculate the capacitance of a parallel-plate capacitor whose plate are 20 cm x 3.0 cm and are separated by a 1.0 mm air gap. * O 51 pF O 50 pF 54 PF 53 PF 2. What is the charge on each plate if a 12V battery is connected across the two plates? * 2.4 x 101-10 C 4.5 x 101-10 C 1.4 x 101-10 C 6.4 x 101-10 C3. What is the electric field between the plates? * 3.2 x 10^4 V/m 2.2 x 10^4 V /m 1.2 x 10^4 V/m 4.2 x 10^4 V/m 4. Estimate the area of the plates needed to achieve a capacitance of 1 F, assuming the air gap d is 100 times smaller or 10 microns (1micron = 1 um = 1x 10^-6 m) * 1016 m 2 916 m12 O 8 6 m 12 O 11 6 m125_ An 8500 pF capacitor holds plus and minus charges of 16.5 x10"-8 C. What is the voltage across the capacitor? * 0 20V 6, A 0.20 F capacitor is desired. What area must the plates have if they are to be separated by a 3.2 mm air gap?* 0 7.2 x10"7 m"2 O 3 x 10A7 m"2 O 8.2 x10"7 m"2 O 2x10"7 m"2 7. If a capacitor has opposite 4.2 uC charges on the plates, and an electric field of 2 kV/mm is desired between the plates, what must each plates area be?* 0 0.12 m"2 O 0.22 m"2 O 0.23 m"2 O 0.13 m"2 1. Series Circuit Problem: Analyze the circuit below. What is the value of V1? * 2- Series Circuit Problem: Analyze the circuit below. What is the value of V2? * 3. Parallel Circuit Problem: Find the currents in the circuit. * 82 13 a + u1 12 + + U3 62 30 V U2 11 = 1A; 12 = 2A; 13 = 3A 11 = 2A; 12 = 2A; 13 = 1A 11 = 1A; 12 = 3A; 13 = 2A O 11 = 3A; 12 = 2A; 13 = 1A