Given a computer with a memory system having a40_bit address, a cache consisting of 4096 blocks each is 16 words. For the following cache types: Direct Mapped (DM). Fully associative (FA). Eight_way set associative (8_way), calculate the following values as specified. (Use paper and pencil to do needed calculations and write the final answer in the given blank space) 1. The size of the offset field = 6 bits 2. DM: size of the index field = 12bits 3. 8_way: size of the index field = 9bits 4. FA: size of the index field - Blank 4 bits 5. DM: The number of sets - Blank 5 6. 8_way: The number of sets = Blank 6 7. DM: The size of the tag field = Blank 7bits 8. 8_way: The size of the tag field = Blank 8bits 9. FA: The size of the tag field =Blank bits 10.FA: The total size of tag bits in the cache = Blank 10kbits