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Given a normally distributed population with = 10and = 2, what value does X have to be so that 80% of the distribution lies below

Given a normally distributed population with = 10and = 2, what value does X have to be so that 80% of the distribution lies below that value?

I know the Z test is used and rearranged to find X, however how do you find Z score based on it being 80% of the distribution?

how do you get the Z score of 0.84? where do you obtain it from?

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