Question
Given a vector of values each of which is larger than zero, for each value, find the closest element that comes before it and is
Given a vector of values each of which is larger than zero, for each value, find the closest element that comes before it and is larger than it. For example, consider the following input vector.
10 | 5 | 9 | 70 | 200 | 50 | 70 | 300 | 75 | 120 | 180 | 130 | 95 | 310 | 360 | 72 | 78 | 400 | 30 | 22 |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
For this input vector, your function should produce the following output vector.
0 | 10 | 10 | 0 | 0 | 200 | 200 | 0 | 300 | 300 | 300 | 180 | 130 | 0 | 0 | 360 | 360 | 0 | 400 | 30 |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
I need help with this assignment both iteratively and recursively. (Two separate main files for each version).
void largest_left_iterative(const std::vector &numbers, std::vector &result); // iterative prototype
void largest_left_recursive(const std::vector &numbers, std::vector &result, int n); // Recursive prototype
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