Given a virtual address and a type of access (Read, Write, eXecute), determine the physical address accessed. If the translation fails or the permissions do not allow that type of access, the correct answer is FAULT. If the translation succeeds and the access type is permitted, the correct answer is the entire physical address to be accessed by the MMU (page frame number and offset).

Given my choices for virtual page number length, how big is my virtual address space in pages? In bytes?

How big is my physical address space in pages? In bytes?

I've perfected my machine's page table implementation. I need you independently verify my implementation. Note: I've expressed all of the numbers in binary. I've decided to use 4 bits for my page offset and 6 bits for virtual page number. The most significant 3 bits are used to index the page directory and the next 3 bits are used to index the corresponding page table. \begin{tabular}{|c|c|c|} \hline \multicolumn{1}{c|}{} & \multicolumn{2}{c|}{ Page Directory } \\ \hline Index & Valid & Page Table \\ \hline 000 & 0 & PT2 \\ \hline 001 & 1 & PT5 \\ \hline 010 & 0 & PT4 \\ \hline 011 & 1 & PT3 \\ \hline 100 & 0 & PT6 \\ \hline 101 & 0 & PT7 \\ \hline 110 & 0 & PT1 \\ \hline 111 & 1 & PT0 \\ \hline \end{tabular} \begin{tabular}{|c|c|c|c|c|c|} \hline \multicolumn{1}{c|}{} & \multicolumn{3}{l}{ Page Table: 5} \\ \hline Index & Valid & PFN & R & W & X \\ \hline 000 & 1 & 011000 & 1 & 0 & 1 \\ \hline 001 & 0 & 000001 & 1 & 1 & 1 \\ \hline 010 & 0 & 001010 & 0 & 1 & 1 \\ \hline 011 & 0 & 000010 & 1 & 0 & 1 \\ \hline 100 & 0 & 101101 & 0 & 1 & 1 \\ \hline 101 & 0 & 000001 & 1 & 1 & 1 \\ \hline 110 & 0 & 000001 & 0 & 0 & 0 \\ \hline 111 & 0 & 010011 & 1 & 1 & 0 \\ \hline \end{tabular} Page Table: 3 \begin{tabular}{|c|c|c|c|c|c|} \hline Index & Valid & PFN & R & W & X \\ \hline 000 & 1 & 101010 & 1 & 1 & 0 \\ \hline 001 & 0 & 111101 & 1 & 1 & 1 \\ \hline 010 & 0 & 100011 & 0 & 1 & 1 \\ \hline 011 & 1 & 000110 & 1 & 0 & 0 \\ \hline 100 & 0 & 000001 & 0 & 1 & 1 \\ \hline 101 & 0 & 001010 & 1 & 1 & 1 \\ \hline 110 & 0 & 000010 & 0 & 0 & 0 \\ \hline 111 & 0 & 101101 & 1 & 1 & 0 \\ \hline \end{tabular}