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Given an arithmetic expression in infix or postfix notation, the goal of this assignment is to : 1. Write a program that converts the expression

Given an arithmetic expression in infix or postfix notation, the goal of this assignment is to :

1. Write a program that converts the expression to another notation using expression trees.

2. Evaluate the expression.

The main idea consists of the following steps :

1. Convert the given (input) expression into a postfix notation (if it is not the case).

2. Construct the expression tree from the postfix representation.

3. Evaluate the expression tree or print it into another notation.

The expression contains only the arithmetic operators +, *, - and /, integers and (, ) if the expression is in infix form. * and / have more priority than + and -. You should leave at least 1 space between operators, operands and symbols (the minus sign("-") for negative numbers should however be attached to the number, -23 for instance).

2.1 Infix to Postfix Conversion

Implement the algorithm that converts an expression from infix to postfix (a description of this algorithm is provided in subsection 3.3.3 of the textbook). Below are some examples for conversion from infix to postfix. -12 + 13 --> -12 13 + 13 + 24 * 35 / 46 --> 13 24 35 * 46 / + ( 4 + 8 ) * ( 6 - 5 ) / ( 3 - 2 ) * ( 2 + 2 ) --> 4 8 + 6 5 - * 3 2 - / 2 2 + * ( ( ( ( 1 * ( 2 + 3 ) ) - 3 ) + 4 ) * 5 ) --> 1 2 3 + * 3 - 4 + 5 *

2.2 Constructing an expression tree from a postfix notation

Implement the algorithm that converts a postfix expression into an expression tree (a description of this algorithm is provided in subsection 4.2.2 of the textbook) . You may reuse the array implementation of the ADT Stack provided by the author (TestStackAr.cpp, StackAr.cpp and StackAr.h are available in the textbook homepage).

2.3 Printing an arithmetic expression from the expression tree

Using the following tree traversal algorithms, write a program that prints an arithmetic expression in a given notation (prefix, infix or postfix) from an expression tree.

2.3.1 Inorder traversal

An overly parenthesized infix expression can be produced by recursively producing parenthesized left expression, then printing out the operator at the root, and finally recursively producing parenthesized right expression. This general strategy (left,node,right) is known as an inorder traversal.

2.3.2 Postorder traversal

The algorithm consists in recursively print out the left subtree, the right subtree, and then the operator.

2.3.3 Preorder traversal

This method consists in printing out the operator first and then recursively print out the left and the right subtrees.

2.4 Evaluating an arithmetic expression from the expression tree

Write a program that evaluates an arithmetic expression represented by an expression tree.

2.5 Marking scheme of the programming part: total = 70pts + 10pts (Bonus)

1. Readability (program style) : 10pts

Program easy to read, well commented, good structured (layout, indentation, whitespace, . . .) and designed(following the top-down approach).

2. Compiling and execution process : 10pts

program compiles w/o errors and warnings robustness : execution w/o run time errors

3. Correctness : 50pts code produces correct results (output) :

(a) infix postfix notation 8pts

(b) infix prefix notation 8pts

(c) postfix infix notation 8pts

(d) postfix prefix notation 8pts

(e) evaluate the expression tree 6pts

(f) Handling numbers with more than 1 digit 6pts

(g) Detecting the type of expression in input(prefix, infix or postfix) 6pts

4. Bonus : 10pts

Handling expressions in prefix form in input 5pts

Detecting the type of errors (missing operator or operand, unknown symbol . . . etc) 3pts

Other features that increase functionality and/or presentation 2pts

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