Given that the side of the square has a length $b-a_1$ find the area of one of the four triangles and the area of the small inner square.

Give the area of one of the triangles followed by the area of the small inner square separated by a comma. Express your answers in terms of the variables a and $b.$

View Available Hint$($s$)$

Hint $1.$ Finding the areas

Recall that the formula for the area of a triangle is $A=(\frac{1}{2})bh,$ where $b$ is the length of the base and $h$ is the height. For a right triangle, the two legs form the base and height.

Also, recall that the formula for the area of a square is $A=s^2,$ where $s$ is the length of a side of the square.