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Given the equation: 2NaCl + Pb(NO3)2 --> PbCl2 + 2Na(NO3) If 2.00 moles of NaCl is reacted with 1.45 moles of Pb(NO3)2 how many grams
Given the equation: 2NaCl + Pb(NO3)2 --> PbCl2 + 2Na(NO3)
If 2.00 moles of NaCl is reacted with 1.45 moles of Pb(NO3)2 how many grams of PbCl2 form?
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