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Given the following communication system where the analog- to-digital (A/D) convert consists of ideal impulse sampler, uniform amplitude quantizer and PCM encoder. Assume the propagation
Given the following communication system where the analog- to-digital (A/D) convert consists of ideal impulse sampler, uniform amplitude quantizer and PCM encoder. Assume the propagation loss is 0 dB (ideal). Si(t) PCM encoder Adder m(t) sampler Polar line code Amplitude quantizer n=4 bits A/D Nit Nct) N.(t),S.(t) receiver Analog output DJA m(t) 1 volt 1 volt -1 volt Also given is the waveform of a deterministic message m(t), band limited to 10 KHz To = period, fo = + = 10 KHz - 10 watts N.(t) = AWGN = additive white gaussian noise, where Sne(t) = - HZ channel or external noise. . N.(t) = input noise to receiver that contains both quantizer noise plus channel noise S(t) = input signal to receiver S.(), no(t) = output signal and noise components If the output signal to noise power ratio iso = (SNR). = 20 dB, n = 4 bits, SN, (w) = 10-8 watts/Hz Determine the following: a)- the output SNR due to quantization noise only b)-the output SNR due to channel noise only c)- the minimum probability of error (Pe = P = BER) d)- the input receiver power for 0 dB propagation loss. Note: The given output (SNR). = = 20 dB include both quantization and channel noise. Given the following communication system where the analog- to-digital (A/D) convert consists of ideal impulse sampler, uniform amplitude quantizer and PCM encoder. Assume the propagation loss is 0 dB (ideal). Si(t) PCM encoder Adder m(t) sampler Polar line code Amplitude quantizer n=4 bits A/D Nit Nct) N.(t),S.(t) receiver Analog output DJA m(t) 1 volt 1 volt -1 volt Also given is the waveform of a deterministic message m(t), band limited to 10 KHz To = period, fo = + = 10 KHz - 10 watts N.(t) = AWGN = additive white gaussian noise, where Sne(t) = - HZ channel or external noise. . N.(t) = input noise to receiver that contains both quantizer noise plus channel noise S(t) = input signal to receiver S.(), no(t) = output signal and noise components If the output signal to noise power ratio iso = (SNR). = 20 dB, n = 4 bits, SN, (w) = 10-8 watts/Hz Determine the following: a)- the output SNR due to quantization noise only b)-the output SNR due to channel noise only c)- the minimum probability of error (Pe = P = BER) d)- the input receiver power for 0 dB propagation loss. Note: The given output (SNR). = = 20 dB include both quantization and channel noise
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