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Given the following instruction executed on ARMv8 in little endian mode: STUR X3, [X4, 0x0] Where the following register values are current: Register Value

 

Given the following instruction executed on ARMv8 in little endian mode: STUR X3, [X4, 0x0] Where the following register values are current: Register Value X3 X4 0x123456789abcdef0 What byte will be stored in address 0x2? What byte will be stored in the same address in big endian mode?

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