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Given the following source code where n = number of data points: for ( int i = 0 ; i < n 1 6 ;

Given the following source code where n = number of data points:
for( int i =0; i < n16; ++i){//
if( i <=0){//
i =1; //
} else {//
i <<1//
}
sum += lg(i); //
}
Note <<= bitshift e.g.[4)10<<1]=[0100)2<<1]->1000)2=8)10
Note recall law of logarithms and exponents.
lg(x)= log2(x)| log(x)= log10(x)| ln(x)= loge(x)
i++ is the same as i = i +1; applied AFTER line is calculated
++i is the same as i = i +1; applied before line is calculated
Assign a cost to each line which will determine the cost function T(n):
T(n)=

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