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Given the following synchronization scheme for a readers / writers problem, what happens if we move the ' rc - - ; ' statement before

Given the following synchronization scheme for a readers/writers problem, what happens if we move the 'rc--;' statement before the 'up(\&mutex);' statement? typedef int sema; sema mutex =1; sema db \(=1\); int rc \(=0 ; \) void reader()\{ while(TRUE)\{ down(\&mutex); rc++; if(rc==1) down(\&db); up(\&mutex); read_db(); down(\&mutex); rc-;; if(rc==0) up(\&db); up(\&mutex); use_data_read(); \}\} void writer()\{ while(TRUE)\{ think_up_data(); down(\&db); write_db(); up(\&db); \} We get better performance, but we may deadlock We get better fairness, but worse performance We get better fairness, but we may deadlock We get better performance, but worse fairnessAccording to the linear regression results (Summary Output) of Portfolios 1 and 2, we can conclude that:
PORTFOLIO 1- SUMMARY OUTPUT
ANOVA
PORTFOLIO 2- SUMMARY OUTPUT
ANOVA
a. Portfolio 2 has better performance but greater diversification
b. The estimated coefficients in portfolio 1 are significant, but those in portfolio 2 are not.
c. Portfolio 1 has better performance but less diversification
d. Portfolio 2 is more aggressive than Portfolio 1
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