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Given the function g(:c) = 8393 + 729:2 + 1929:, find the first derivative, g'(:c). g'(:c) = 24m2+144m + 192 a Notice that g'(m) =
Given the function g(:c) = 8393 + 729:2 + 1929:, find the first derivative, g'(:c). g'(:c) = 24m2+144m + 192 a\" Notice that g'(m) = 0 when a: = 2, that is, g'( 2) = 0. Now, we want to know whether there is a local minimum or local maximum at m = 2, so we will use the second derivative test. Find the second derivative, 9' ' (as). W) = Evaluate g"( 2). 9\"( - 2) =
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