Given the function g(:l:) = 4:1:3 + (in:2 __ 2409:, find the first derivative, g'(a:). 913) = Notice that g'(:z:) = 0 when m = - 5, that is, g'( - 5) = 0. Now, we want to know whether there is a local minimum or local maximum at a: = 5, so we will use the second derivative test. Find the second derivative, 9' '(m). N) = Evaluate g' '( 5). .g\"(s)=\\ Based on the sign of this number, does this mean the graph of g(:c) is mp arm at :c = 5? - it? At 3 = 5 the graph of g(a:) is Based on the concavity of g(a:) at :t: = 5,'does this mean that there is a local minimum or local maximum at m = 5? At a: = 5 there is a local Question Help: El Video 0 Post to forum