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Given the funktion f: IR {-3} IR with f(x) = a) Show by using polynomial division that, 2x+7 x+3 f(x)=2+ 1 for all x

 

Given the funktion f: IR \{-3} IR with f(x) = a) Show by using polynomial division that, 2x+7 x+3 f(x)=2+ 1 for all x R\{-3} +3 hold and sketch the graph of the function f by developing the graph of the corresponding basic function. b) Then graphically and analytically determine all solutions to the inequality 2x+7

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