Given the interface between two materials (tissue and Nal), and an initial KERMA of 100 J/kg at the surface (A) of tissue, calculate KERMA at locations B and C for 150 keV photons incident as shown below. = 0.1466 cm tissue 9 = 0.5663 cm2 g Ptissue = 1 9 Nal crn 3 = 0.02733 cm : p tissue Her p = 0.4099 cm PNal = 3.67 9 Nal g cmn3 Tissue Nal 150 kev photons 2 cm 2 cm