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Given the specific heat of lead as being 0.0305 cal/(g * C ), what is the final temperature if you mix 579 g of lead

Given the specific heat of lead as being 0.0305 cal/(g * C), what is the final temperature if you mix 579 g of lead at 100 C with 39.4 g of water at 75 Cin an insulated container? (Give the final answer in degrees Celsius)

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