Given the underneath fragment code that is written in C language, Write down the function with domain and codomain then prove that function is NOT bijective (One to one and Onto)? Show ALL Your Works. IT'S NOT ENOUGH to give a counterexample, you have to check both (Surjectivity and Injectivity) void fun(int *m, int *n){ *m=(*m) * (*n); *n=(int)*(pow (*n,2)-4); }