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Given y=[ 2 +(x2+1)4 ]3; Find y' O y'=24x (x2+1)3 [ 2 +(x2+1) 4 12 O y' = 4 (x2+1)9 O (E) None of the

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Given y=[ 2 +(x2+1)4 ]3; Find y' O y'=24x (x2+1)3 [ 2 +(x2+1) 4 12 O y' = 4 (x2+1)9 O (E) None of the choices O y' = 64 (x2+1)9Find the derivative: y = (3x2 - 2x ) Vx5 - 2x + 2 O dy (3x2-2x) (5x4-2) = dx + (x5 - 2x + 2) (6x - 2) 2Vx5 -2x+2 O (E) None of the choices O dy (3x2-2x) (5x4-2) = dx + Vx5 - 2x +2 2Vx5 -2x+2 O dy 27x6+15x4-15x2+30x-8 dx Vx5-2x+2 O dy 27x6-14x5-30x2+36x-8 dx 2Vx5 -2x+2Given y = (1 - V2x ) ; Find dy/dx O dy N dx = -3(1 - V2x V2x O dy N dx = -3(1 - V2x O dy dx = 3 (1 - V2x ) - ( 2 x ) - O (E) None of the choices O dy dx = 3(1 - V2x 2 (2x)In the Four-Step Rule, why is the cancellation of the Ax terms allowed even if Ax - 0 is in the denominator (division of zero by zero)? O (E) None of the choices O The definition of a limit, which is the best approximation of a function evaluated around an approached value, allows the cancellation since Ax is not exactly equal to zero. O It is the definition of a derivative. O Using the definition of a limit, if the denominator was not cancelled out then it would not be possible to arrive at a function describing the slope of the tangent line to a function at a given value of x

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