Given y=(x+2)(2r2+3)3 find the equation of the tangent line to this function when x = 1. First find the point on this function and the slope of the tangent line to this function when x = 1. Next use these to find the equation of the tangent line to this function when x = 1. Finally, put this equation in slope intercept form. All work must be shown!! %3D %3D Point on function when x = 1 is (1, Slope of tangent line when x = 1 is Equation of tangent line in slope intercept form is: