Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Glucose (C6H12O6) is the main source of energy in the metabolism. When 0,3212g og glucose is combusted/burnt in a bomb calorimeter at 298,15 K (T

Glucose (C6H12O6) is the main source of energy in the metabolism. When 0,3212g og glucose is combusted/burnt in a bomb calorimeter at 298,15 K (T surrounding) the change in temperature was 7,793 K. The heat capacity of the calorimeter is 641 J/K. Calculate ∆cHm and ∆cUm for the combustion.

Step by Step Solution

3.45 Rating (165 Votes )

There are 3 Steps involved in it

Step: 1

Molecular weight of sucrose 1806 gmol Reaction given ... blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Business

Authors: Ricky Griffin, Ronald J.Ebert, Frederick Starke, Melanie Lang, George Dracopoulos

8th Canadian Edition

133354261, 978-0133354263

More Books

Students also viewed these Chemistry questions