Good day! Please do help me with this Physics subejct please. The first picture is the problem, and in the second picture is the answer to that problem. Now, all i want and need is to how to read or how did i come up to that answers. I just need a complete explanation word by word, symbol by symbols. Please do help me, i just badly needed it. I promise to give a perfext scoee as a feedback. Pleasee... Thank you very much....

3 . ) a . ) co - 2 7 T CO = 271 1- 50D x (0.500) = - 0.120 CO = 4.19 X (t ) = Acos cot X (0-500) = 0-240 cos (4-19t) b . ) Vx = - WAsin (wt ) = - (4-19) 0.240 sin (4.19 t ) V = - 0.87 . . The sign indicates that the direction of the force is going to the left C. ) X = A sin cot t = arcsin /-2180 0.240 Asin co Asin co 4- 19 t = x Arcsin) Asinco t = 0.20s CO VY = m (ARXz ) S 0.20s [10. 240 m ) ? - ( - 0 . 180 m ) 2 V = 4.98 m/s3. A 0.0200-kg bolt moves with SHM that has an amplitude of 0.240 m and a period of 1.500 s. The displacement of the bolt is +0.240 111 when t = 0 3. Compute a. the displacement of the bolt when t = 0.500 s. {2 pts} b. the magnitude and direction of the force acting on the bolt when t = 0.500 s. [3 pts] c. the minimum time required for the bolt to move from its initial position to the point where x = 0.100 m. :3 pts] d. the speed of the bolt when x = 0.180 m. {1 pts}