Good Evening, I have some questions that I need the answers to please.

1.) Part 6?

Coffee: The National Coffee Association reported that 62% of U.S. adults drink coffee daily. A random sample of 300 U.S. adults is selected. Round your answers to at least four decimal places as needed. Part 1 of 6 (a) Find the mean JA. The mean un is 0.62 . Your answer is correct. Part 2 of 6 V (b) Find the standard deviation GA. The standard deviation on is | 0.0280 . Your answer is correct. However, you don't need to put zeros at the end of the number. Alternate Answer: The standard deviation on is 0.028. Part 3 of 6 V (c) Find the probability that more than 63% of the sampled adults drink coffee daily. The probability that more than 63% of the sampled adults drink coffee daily is 0.3605(c) Find the probability that more than 63% of the sampled adults drink coffee daily. The probability mat more than 63% ofthe sampled adults drink coffee daily is 0.3665 . I Your answer is correct. {d} nd the probability that the proportion of the sampled adults who drink coffee daily is between 9.56 and I[1.6'1. The probability mat the proportion of the sampled adults who drink coffee daily is between 0.56 and 0.64 is 0.?462 . I Your answer is correct. (e) Find the probability that less than 68% of sampled adults drink coffee daily. The probability mat less man 63% of sampled adults drink coffee daily is 0.9339 . - Your answer is correct. {f} Would it be unusual if less than 59% of the Sampled adults drink coffee daily? It {Choose one) 1' be unusual if less than 59% of the sampled adults drink coffee daily, since the probability is D. w o u Id would not Future scientists: Education professionals refer to science, technology, engineering, and mathematics as the STEM disciplines. A research group reported that 26% of freshmen entering college in a recent year planned to major in a STEM discipline. A random sample of 90 freshmen is selected. Round the answer to at least four decimal places. Part 1 of 6 Is it appropriate to use the normal approximation to find the probability that less than 29% of the freshmen in the sample are planning to major in a STEM discipline? It is appropriate to use the normal curve, since np = 23.4 > 10 andn (1 - p) = 66.6 2 10. . Your answer is correct. Part 2 of 6 Find the probability that less than 29% of the freshmen in the sample are planning to major in a STEM discipline The probability that less than 29% of the freshmen in the sample are planning to major in a STEM discipline is |0.7419 . Your answer is correct. Part 3 of 6 A new sample of 150 freshmen is selected. Find the probability that less than 32% of the freshmen in this new sample are planning to major in a STEM discipline. The probability that less than 32% of the freshmen in the sample are planning to major in a STEM discipline is | 0.9531 Your answer is correct.Find the probability that the proportion of freshmen in the sample of 150 who plan to major in a STEM discipline is between 0.31 and 0.37. The probability that the proportion of individuals in the sample of 150 Iwho plan to major in a STEM discipline is between 0.31 and 0.37 is -. I Your answer is correct. Find the probability that more than 34% of the freshmen in the sample of 150 are planning to major in a STEM discipline. The probability that more than 34% of the freshmen in the sample of 150 are planning to major in a STEM discipline is D. Is it reasonable to treat the following as a sample from an approximately normal population? Explain. (a) The following dotplot illustrates a sample. The dotplot reveals a large degree of skewness 1' . Therefore, we treat this as a sample from an approximately normal population. - Your answer is correct. (b) The following boxplot illusirates a sample. F 8 El 10 2 3 4 5 5 The boxplot reveals none of these features Y . Therefore, we treat this as a sample from an approximately normal population. I Your answer is incorrect. Correct Answer: The boxplot reveals none of these features. Therefore, we can treat this as a sample from an approximately normal population. (d) The following stemandleaf plot illustrates a sample. 58 011245569 2445 l? wmqmm-ih- 105 11'0I The stemandleaf plot reveals outlierfs) Y . Therefore, we treat this as a sample from an approximately normal population. I Your answer is incorrect. (d) The following stemandleaf plot illustrates a sample. 58 011245569 2445 17 6040'th 10 11 The stemandleaf plot reveals outlier{s) 1" . Therefore, we a large degree of skewness more than one distinct mode none of these features l Your answer is incorrect