Good Morning, I have some questions that need answers, please.

1.) Part 3? Is/ Is not?

Watch your cholesterol: A sample of 315 patients between the ages of 38 and 82 were given a combination of drugs ezetimibe and simvastatin. They achieved a mean reduction in total cholesterol of 0.94 millimole per liter. Assume the population standard deviation is o = 0.17. Part 1 of 3 (a) Construct an 80% confidence interval for the mean reduction in total cholesterol in patients who take this combination of drugs. Round the answer to at least two decimal places. An 80% confidence interval for the mean reduction in cholesterol is | 0.93 0.95 Part 2 of 3 (b) Should this confidence interval be used to estimate the mean reduction in total cholesterol for patients between the ages of 89 and 95? The confidence interval should not be used to estimate the mean reduction in total cholesterol for patients between the ages of 89 and 95. Part: 2 / 3 Part 3 of 3 (c) Based on the confidence interval constructed in part (a), is it likely that the mean reduction in cholesterol level is less than 0.90? The mean reduction in total cholesterol (Choose one) |likely to be less than 0.90. X 5SAT scores: A college admissions officer takes a simple random sample of 100 entering freshmen and computes their mean mathematics SAT score to be 458. Assume the population standard deviation is o = 111. Part 1 of 4 (a) Construct a 99.9% confidence interval for the mean mathematics SAT score for the entering freshman class. Round the answer to the nearest whole number. A 99.9% confidence interval for the mean mathematics SAT score is 421 495 Part 2 of 4 (b) If the sample size were 120 rather than 100, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be smaller , since an increase v in the sample size will decrease the standard error. Part: 2 / 4 Part 3 of 4 (c) If the confidence levels were 80% rather than 99.9%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) , since (Choose one) |in the confidence X 5 level will (Choose one) the critical value Za/2. decrease IncreasePart 3 of 4 (c) If the confidence levels were 80% rather than 99.9%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) , Since (Choose one) V in the confidence level will (Choose one) th larger X 5 smallerPart 3 of 4 (c) If the confidence levels were 80% rather than 99.9%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) , Since (Choose one) in the confidence X level will (Choose one) an increase 5 the critical value Za/2. a decreaseEat your cereal: Boxes of cereal are labeled as containing 14 ounces. Following are the weights, in ounces, of a sample of 16 boxes. It is reasonable to assume that the population is approximately normal. 14.07 13.98 14.16 14.17 14.11 14.03 14.16 13.98 14.06 14.05 14.12 14.13 14.19 14.17 14.05 14.04 Send data to Excel Part 1 of 2 (a) Construct a 95% confidence interval for the mean weight. Round the answers to at least three decimal places. A 95% confidence interval for the mean weight is 14.056