Grades - Mohammad Yassine X VA MATH180: HW21- Sec 4.7 (F202 x do Octave Online . Cloud IDE compe x M Inbox (111) - myassine3@hawkr x Open orders - EssayPro.com * A baseball team plays in a stadi x Course Hero + X a webassign.net/web/Student/Assignment-Responses/submit?dep=32016420&tags=autosave#question4709880_8 5th GradeAlpha.pdf VitalSource Booksh.. bank mobile FA Order 3570395 - Es.. b Success Confirmati V Z-Library Psychology in Ever. = Precalculus 2e- Op.. XYZ Homework - H. PB Technical and Prof. My Course- Macroe. MindTap - Cengage. Submit Answer 14. [-/9 Points] DETAILS SCALCET9 4.7.AE.006. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Example 6 Video Example () A store has been selling 300 TV monitors a week at $450 each. A market survey indicates that for each $10 rebate offered to buyers, the number of monitors sold will increase by 20 a week. Find the demand function and the revenue function. How large a rebate should the store offer to maximize its revenue? Solution If x is the number of monitors sold per week, then the weekly increase in sales is . For each increase of 20 units sold, the price is decreased by $10. So for each additional unit sold, the decrease in price will be -x 10 and the demand function is 20 P(x) = 450 - (x - 300) = 600 - The revenue function is R(x) = xp(x) = Since R'(x) = we see that R'(x) = 0 when x = . This value of x gives an absolute maximum by the First Derivative Test (or simply by observing that the graph of R is a parabola that opens downward). The corresponding price is P(600) = and the rebate is 450 - 300 = . Therefore, to maximize revenue, the store should offer a rebate of $ Need Help? Read It Submit Answer Home My Assignments + Request Extension Copyright @ 1998 - 2023 Cengage Learning, Inc. All Rights Reserved | TERMS OF USE PRIVACY US Jul 28 8:04 2