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Group Statistics Std. Std. Error Gender N Mean Deviation Mean Likes to Go Out Socially Male 259 4.35 1.186 .074 Female 145 4.59 1.064 .088
Group Statistics Std. Std. Error Gender N Mean Deviation Mean Likes to Go Out Socially Male 259 4.35 1.186 .074 Female 145 4.59 1.064 .088 Try New and Different Male 259 5.53 1.854 .115 Thing Female 145 5.14 1.862 .155Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of Sig. (2- Mean Std. Error the Difference F Sig. df tailed) Difference Difference Lower Upper Likes to Go Out Socially Equal variances .576 .448 -2.038 402 .042 -.242 119 -.475 -.009 assumed Equal variances not -2.101 326.041 036 -.242 115 -.468 -.015 assumed Try New and Different Equal variances .952 .330 2.010 402 .045 .387 .193 .009 766 Thing assumed Equal variances not 2.008 297.095 .046 .387 .193 .008 .767 assumedSECTION 2 Question 1: An important insight into restaurant goers' behavior concerns whether men and women differ when it comes to likes to go out socially and try new and different things. Is there a relationship between gender and these variables? To determine whether relationships exist, you need to test the mean scores on LIKES TO GO OUT SOCIALLY and TRY NEW AND DIFFERENT THINGS for GENDER to see if there is a difference. Use this output to answer the question. Specifically: 1. Why is this an appropriate method? https://calstatela.instructure.com/courses/71721/pages/spss-assignment-instructions?module_item_id=4007911 1/2 4/14/22, 8:00 PM SPSS Assignment Instructions: BUS 5930-01 (31057) 2. Is there a difference between the mean scores of likes to go out socially and try new and different things for gender? What is the difference if there is one, and is it statistically significant? How do you know? 3. If there are statistically significant differences, use them to describe men and women restaurant-goers and how this information can guide your manager's marketing strategy
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