$H_{2}S$ is absorbed from air to water in a wetted wall tower. The water flows as a film on the flat wall. The absorption of $H_{2}S$ takes place at $187\mathrm{.}429$kPa total pressure and $300K.$ The mass transfer coefficient for the gas phase $($from bulk gas to liquid$-$air interface$)$ has been determined to be as $k_c^{\text{'}}=8\mathrm{.}6{10}^{-4}\frac{m}{s}.$ At a given point in the wetted$-$wall tower the mole fraction of $H_{2}S$ in the liquid at the liquid$-$air interface is $3\mathrm{.}1{10}^{-5}$ and partial pressure of $H_{2}S$ in air $p_A=6\mathrm{.}07$kPa. Henry's law for the equilibrium relation is $p_A=61206\mathrm{.}721x_A(kPa),$ where $x_A$ is the mole fraction of $H_{2}S$ in liquid film. Determine:

$($a$)k_G$

$($b$)$ partial pressure at the interface $($point $2)$

$($c$)$ the rate of absorption of $H_{2}S$ in $kg-\frac{\text{m}\text{o}\text{l}}{h-m^2}.$