h bobivo = lim ( xth ) ? ( *+ 1 ) - x* (xth+ 1 ) lim h ( 2x 3 + 2 x+ xh th -x?)_ li ( Xth +1 ) (X+1 ) K (xth + 1 ) ( x + 1 ) h substitut #3. Determine dy for each of the following, and simplify your answer: = 2X+X dx ( X+ 1 ) [6] ( a ) y = (2x - 1)3 (x2 + 1)2 (b ) V = ". f' (x ) y = 3 ( 2 X - 1) = [ 27 ( x 2 + 1 ) 2 + ( 2 X - 1 ) ' [ 2 ] ( x 2 + 1 ) [ 2 x ] y' = 6 ( 2X- 1) 2 ( X 2+ 1 ) 2 + 4x (2X-1)' ( x2+ 1 ) = ( 2X - 1 ) 2 ( X 2 + 1 ) [ 6 ( x 2 + 1 ) + 4x ( 2X-1)] ( 2 X - 1 ) 2 ( X 3 + 1 ) [ 6 x 2 + 6 + 8 x 2 - 4 x ] 17( y = 2 ( 2x- 1) ? ( X 2+ 1 ) (1 x 2 2x+ 3 ) ( 2 X - 1) 2 ( X 2 + 1 ) ( 14 x 2 - 4 X+ 6 ) [6] (C) y = cos \\Vx- +1) (d) J = 2* + 1 4= cos ( x2+ 1) /2 8