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Hand Welding D = (shift Length)/T T = (8)/2[(L-900/5] L is the measured TWA in dBA Solve [(L - 90)/5] first for an exposure of
Hand Welding D = (shift Length)/T T = (8)/2[(L-900/5] L is the measured TWA in dBA Solve [(L - 90)/5] first for an exposure of 81.3 dBA (81.3 - 90)/5 = -1.74 Then solve 2(-1.74) = 0.2994 8/0.2994 = 26.7 For a 12-hour shift Dose = 12/26.7 = 0.4% 6
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