HANDWRITTEN THEN BOX THE FINAL ANSWERS. PLS WRITE LEGIBLY

Activity # 2 Part I Temperature Altitude Variation Solve for the temperature IF the given height is 7500mi Solve for the altitude if the given temperature is KAK and the Tris 288 16k S IS9.1 Ans: For the temperature at a given altitude of 7,500 m. using the standard lapse rate of 6 5 'c per kilometer. NOW , Multiplying the lapse rule by the altitude (in kMJ 6. 5 c / Km x 7.5 km = 48. 75 C. subtracting this change in temperature from the standard temperature at sea level, which is 288,16 K ( 288 . 16 k - 48. 75. ( ) + 273 1 512. 56 K The temperature at an altitude of 71500 m is 512, 56 K. Any For the altitude at a given temperature of 144k, we will subtract this temperature from the standard temperature at sea level ( 288. 16 K ) 288 . 16 K - 144 k = 144. 16 K Dividing this temperature change by the lapse rate of 65 ' c / KM. 144.16 k 6. 5. C / km = 28. 18 km Therefore, the altitude at a temperature of 14 4 K is 22 . 18 KM //