Hang one of the mystery weights in the x direction (180). We now attempt to represent this unknown force F as the sum of two forces with given magnitude by varying the directions 61 and 92. To this aim, hang a fixed weight of 2009* (1809* plus 209* for the hanger) in the first quadrant (F1) and another of 1509* (1309* plus 209* for the hanger) in the forth quadrant (F2), as shown in the figure on the right. Now adjust the two angles 31 and 92 until the ring is centered. Four to ve repeated measurements allow you to determine the best values and the estimated uncertainties for the two angles. Present the repeated measurements in a data table. Determine the average and the errors of the two angles. Using eqs.1-3, calculate the magnitude of the unknown force I?" and its error. For this you must remember how to calculate the error of sine or cosa when the error of 9 is given. Determine the mass of the mystery weight by using a balance and compare this value with the result obtained with the Force Table. Finally, note that the y-component of F\" is zero. Check if our expectation of F1y=F2y is satisfied. Write a conclusion about the outcome of this part of the experiment. \f\f\f