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Haskell: Given the following code, prove for finite lists by using structural induction, given: append:: [a] => [a] => [a] append ys = ys append
Haskell: Given the following code, prove for finite lists by using structural induction, given:
append:: [a] => [a] => [a] append ys = ys append (x:xs) y = x: (append xs ys) filter p [] = 0 filter p (a:as) pa = a: (filter p as) I otherwise = filter p as that filter p (append xs ys) append (filter p xs) (filter pys) append:: [a] => [a] => [a] append ys = ys append (x:xs) y = x: (append xs ys) filter p [] = 0 filter p (a:as) pa = a: (filter p as) I otherwise = filter p as that filter p (append xs ys) append (filter p xs) (filter pys)Step by Step Solution
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