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having some issues with this review page and how to create the stemplot for the data. Would like some help on how to solve the
having some issues with this review page and how to create the stemplot for the data. Would like some help on how to solve the questions including all parts. Thank you for the help in advance. Really would like get this done and have something to study later on.
DECLI OF U.S. Dollars BRITISH 5 $4.86 POUND $4.030 $2.80 $2.60 co Copyright 1975 by the Associated Press. Reproduced by permission $2.40 $2.039 O 1925 1939 1949 1967 1971 1975 FIGURE 4.32 A newspaper's graph of the value of the British pound, for Exercise 4.67. FIGUR (a) Make a stemplot of the data, but split the stems (see Exercise 4.33, page 242). the 50 st (b) A graph of only 6 observations gives little information, so we proceed to compute the mean and standard deviation. 4.71 Lal (c) Find the mean from its definition. That is, find the sum of the 6 observations * = $5. and divide by 6. (d) Find the standard deviation from its definition. That is, find the distance of (a) Why each observation from the mean, square the distances, then calculate the standard (b) Sup deviation. two gro (e) Now enter the data into your calculator and use the mean and standard salary, a deviation buttons to obtain x and s. Do the results agree with your hand calculations? 4.72 C card st 4.69 Roller coaster fatalities Data are provided on roller coaster accidents and studen fatalities in the United States in the data set COASTERS. debt. H (a) What is the mean number of roller coaster fatalities? (b) Plot a histogram and a boxplot in the same calculator screen. Is the mean a suitable measure of center, or should the median be used? Explain. 4.70 State SAT scores Figure 4.33 on the facing page is a histogram of the aver- age scores on the mathematics part of the SAT exam for students in the 50 states Fred and the District of Columbia. The distinctive overall shape of this distribution implies that a single measure of center such as the mean or the median is of little value in describing the distribution. Explain whyStep by Step Solution
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