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HDL 39 40 40 40 40 42 45 46 47 47 47 47 48 50 50 50 55 55 55 56 56 57 59 60

HDL
39
40
40
40
40
42
45
46
47
47
47
47
48
50
50
50
55
55
55
56
56
57
59
60
62
62
65
66
66
68
68
70
72
75
76
76
77
78
78
78
x (HDL) 2308
= (x) 2308 40 (N) 57.7
12.53634716

Is my computation for the mean and standard deviation, correct?

Given the mean and standard deviation computed above, if the intervention program targets women with low HDL (HDL < 50), what percentage will be included? Show computation or the use of an online calculator. Show Z score.

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