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height, but the full 10,000 kg is accelerated. (a) Find the useful power output (in W) of an elevator motor that lifts a 2700 kg

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height, but the full 10,000 kg is accelerated. (a) Find the useful power output (in W) of an elevator motor that lifts a 2700 kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2700 kg is raised 124816.67 * W (b) What does it cost (in cents), if electricity is $0.0900 per kW . h? cents Additional Materials Reading 5. [-/2 Points] DETAILS OSUNIPHYS1 7.4.P.078. MY NOTES A man of mass 80 kg expends 1,760 W running up a flight of stairs. ASK YOUR TEACHER PRACTICE ANOTHER The man consumes approximately 1.21 x 10' J (2,900 food calories) of energy per day in maintaining a constant weight. What is the average power he produces over a day (In W)? W Compare this with his power production when he runs up the stairs. running up stairs weight maintenance Additional Materials Reading OSUNIPHYS1 7.4.P.082. 6. [-/1 Points] DETAILS Suppose that the engine of a 1,900 kg automobile has a maximum power output of 45 hp. What is the maximum grade (in percent) that the automobile can climb at 39 km/h if the drag force on it Is 390 N? MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER

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