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Helium gas with a volume of 3.20 L, under a pressure of 0.160 atm and at a temperature of 45.0 C, is warmed until both

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Helium gas with a volume of 3.20 L, under a pressure of 0.160 atm and at a temperature of 45.0" C, is warmed until both pressure and volume are doubled. Note that 1L = 0.001m, latm = 1.013 - 10' Pa , and temperature in Kelvin is related to the temperature in degrees Celsius as follow: T(Kelvin) - T(Celsius) + 273. What is the final temperature? Express your answer in degrees Celsius. Report the result with three significant figures. AEQ T PC

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