hello,

can someone please explain to me exactly how the h's are eliminated on line 5-6.

what happened to 3h^2?

where did the h from 6xh go?

how do you know what h needs to be eliminated vs which h doesn't?

if you can, please try to make it as simple as possible... i am still learning.

thank you very very much!!

10. At what point on the parabola y = 3x2 + 2x is the tangent line parallel to the line y = 10x - 2? Solution: Find derivative of y = 3x2 + 2x using First Principles. f '(x) = lim /(xth) f(x) h-0 h f '(x) = lim [3(xth) 2+2(xth)]-(3x2+2x) h-0 h f '(x) = lim [3(x2+2xh+h2)+2x+2h]-3x2-2x h-0 h f '(x) = lim 3x2+6xh+3h-+2x+2h-3x2-2x h-0 h f '(x) = lim 3x2+6xh+3h-+2x+2h-3x--2x h-0 h f '(x) = lim( Exh+2h) h-0 h f '(x) = 6x+2 y = 10x - 2 m = 10