Hello,

Could someone check my answer and let me know please? I'm quite certain that it's correct but like to double check first. Thank you.

Answer:v=1308 m s or = 1310 m s (in 3 sig-figs). Explanation: Giving: Initial vertical speed. u=0ms Acceleration due to free fall, a = 4.36 m s [from my answer ii) Because free fall is happening, the lander will experience acceleration along vertically downward direction. Knowing from kinematics, v=u + at Time of fall, t= 300 s Inserting the values the final speed v: =0ms+ (436 ms3).(300s) ={ms?xs} = {me+5} = {m} ={1} =1308ms or = 1310 m s (in 3 sig-fig) Therefore, the vertical speed of the lander after 300 seconds is approximately 1310 m s in three significate figures. The satellite will drop a small lander onto the moon surface. At release, the vertical speed of the lander is zero. Neglecting all other forces except gravity, which you can assume to be constant, use your answer (4.36 m s2) to calculate the vertical speed of the lander after 300 s. Use the appropriate number of significant figures