Hello, I lost my calculator, so I need help with solving these answers

Step-by-Step: How Old is it? (Practice with logarithms) In this Step-by-step assignment you'll be using the pre-electronic computing method involving logarithms to find (approximately) how old something is in seconds. Step Instructions Results, including your work 1 Think of something you'd like to find the age of in seconds. It could be you, your car, your dog, or whatever. Write down this thing's age in years. Age (in years) = 12 (dog) [ (this year) - (its 'birth' year) ] 2 We'll be using the common logarithms (base-10) for this calculation. Use your calculator to calculate the common logarithm of the age in years. Write down as log(age)= many decimal places as you can. This helps the accuracy. (The 'logarithm' steps would have been done before calculators using a table of logarithms that someone painstakingly constructed.) 3 Find the logarithm of the number of days in a year (365.25). Write as many decimals as you can. log(365.25) = 4 Find the logarithm of the number of seconds in a day (86400). Write as many decimals as you can. log(86400) = 5 Now ADD the numbers from steps 2, 3, and 4 together. log(age) + log(365.25) + log(86400) (You can do this on your calculator, too.) (Without logarithms, you would multiply age*365.25*86400. With a modern calculator this is easy, but imagine doing this the long-hand way, digit-by- digit, adding columns, etc.) 6 Convert the number from step 5 back from logarithmic Age in seconds = 10step_5_answer form to a regular number by using the inverse logarithm, or anti-logarithm, function. This is the function 10%. (This step would use the same logarithm table as before, but used in reverse.) Check your answer using a calculator and regular multiplication (age*365.25*86400). Do the two numbers agree? (The exact same procedure can be done using the natural log function, In(), and its inverse, e", along with a natural log table. You can try this out, if you like. Do the above, but replace log() with In() and 10" with ex.)