Hello, I need help improving my C++ code by replacing the if statements with a while loop. Thanks.

Code:

#include #include #include

using namespace std;

int main() {

fstream output; long int num; // you cant use small c, as cout is a keyword in c++. char exit = NULL;

output.open("output.txt", fstream::out);

output

if (output.is_open()) {

while (exit != 'n' && exit != 'N' || num >= 2000000000 && num

cout > num;

if (num > -10 && num -100 && num = 10 && num -1000 && num = 100 && num -10000 && num = 1000 && num -100000 && num = 10000 && num -1000000 && num = 100000 && num -10000000 && num = 1000000 && num -100000000 && num = 10000000 && num -1000000000 && num = 100000000 && num -10000000000 && num = 1000000000 && num

if (num >= 2000000000 || num

cout > exit; } output.close(); } else cout

return 0;

}

Requirements:

Write a program to read an integer number and find its number of digits (for example, 3459 has 4 digits and 125860 has 6 digits). The program should be designed in a way that the user could test as many numbers as desired without leaving the program. Use only long integer (int or long int) data type in this problem; however make sure that the program rejects any input outside the long integer data range. The outputs of the program should be written to an output file having a format similar to the following table. VALUE ENTERED NUMBER OF DIGITS 1241 19 5684900 uw - NA 1267678901 -153 62000 Test the program for at least seven integer values between + 2,000,000,000 and a number outside the long int data range. Remember to submit a copy of the program file and a copy of the output file. Note: You should use while or do-while loop in this assignment