Hello I need help with these multiple choice questions. For a good review please answer all questions (with the correct letter) and be specific. Thank you

Question 10 (1 point) -Listen The amount of work an 118 W electric mower can do in 3.0 min is: O a) 3.9 x 101 J Ob) 2.5 x 10- 2 J c 1.5 x 10 0 J O d) 21 x 104 J O el 3.5 x 102 JQuestion 14 (1 point) Listen In which case is positive work being done? O a) The work done by air resistance on a ball as the ball, which was initally at rest, falls 3.0 m down towards Earth. b) A cart moving at a constant velocity of 10 m/s [W] when a 0.5 N [E] force is applied. O c) The work done by air resistance as a baseball is thrown horizontally towards the catcher. d) Earth applies a force on the Moon as the Moon travels one complete rotation in orbit around the Earth. e) An eastward force is applied to an eastward moving soccer ball that is already moving at a constant velocity to increase its speed in that direction. Question 15 (1 point) Listen An air hockey paddle hits a 48 g stationary puck with a force of 12 N. The puck travels 5.0 x 10- cm on the frictionless surface while the force is applied to the puck. How much work was done on the puck? O a) 6.0 J O b) 6.0 x 102 J c) 0.58 J O d) None of these options is correct. O e) 2.4 x 10 ? JQuestion 18 (1 point) Listen The capacity to do work is known as O a) energy O b) work O c) heat O d) energy transformation O e) efficiency Question 19 (1 point) Listen An air hockey paddle hits a 48 g stationary puck with a force of 12 N. The puck travels 5.0 x 10 cm on the frictionless surface while hte force is applied to the puck. At the moment when the puck has 4.0 J of work done on it, how fast will it be travelling? O a) 166 m/s b) None of these options are correct. O c) 15 m/s O d) 9.1 m/s O e) 13 m/sQuestion 11 (1 point) Listen A string hangs motionless over a frictionless pulley as shown in the diagram below. A 1.0 kg mass hangs on one side of the pulley and 2.5 kg mass hangs on the other side. Both masses are initially at rest with the 1.0 kg mass on the floor. 1.0 KE 0.50 m If the kinetic energy of the two masses was known just before the 2.5 kg mass hits the floor, the velocity of each mass could be calculated: a) by doubling the kinetic energy and dividing by 3.5 kg O b) none of these methods will give you the speed of the two masses. O c) by letting the kinetic energy equal to speed of the two masses. O d) by doubling the kinetic energy, dividing it by 3.5 kg and taking the square root. O e) by taking the square root of the kinetic energy, dividing by 3.5 kg and doubling.Question 5 (1 point) Listen The amount of work done to stop a bullet travelling through a tree trunk a distance of 50.0 cm with a force of 2.00 x 102 N is: O al -4.00 x 102 J O b) +4.00 x 102 J O c) 1.00 x 102 J O d) +1.00 x 104 J O e) +1.00 x 102 JQuestion 12 (1 point) Listen A 500.0 g bird has gathered a breakfast of ten juicy worms for her young offspring. Each worm has a mass of 5.00 g and must be delivered to the waiting offspring 10.0 m up in the tree. Calculate the least amount of work the mother bird will have to do to feed breakfast to her little birds. O a) 5.00 x 102 J O b) 5.39 J O c) 5.39 x 101 J O d) None of these options are correct O e) 2.5 x 105 JQuestion 17 (1 point) Listen A string hangs motionless over a frictionless pulley as shown in the diagram below. A 1.0 kg mass hangs on one side of the pulley and 2.5 kg mass hangs on the other side. Both masses are initially at rest with the 1.0 kg mass on the floor. LOK 0.50 m The gravitational potential energies of the two masses in their initial positions are: O a) 0 J and 12 J respectively O b) None of these options are correct. O c) 0 J and - 12 J respectively O d) 0 J and 1.3 J respectively O e) 9.8 J and 20 J respectivelyQuestion 1 (1 point) Listen A string hangs motionless over a frictionless pulley as shown in the diagram below. A 1.0 kg mass hangs on one side of the pulley and 2.5 kg mass hangs on the other side. Both masses are initially at rest with the 1.0 kg mass on the floor. 2.5 1 0.50 m After release, the 2.5 kg mass will rest on the floor and the 1.0 kg mass will be elevated. The new potential energies of the 2.5 kg mass and 1.0 kg mass will be: a) None of these options are correct. Ob) O J and 4.9 J respectively c) 0 J and 15 J respectively d) O J and 9.8 J respectively O e) 0 J and 12 J respectivelyQuestion 2 (1 point) Listen A 2.0 kg grapefruit is tossed at a speed of 5.0 m/s from a roof that is 6.0 m above the ground. To determine the kinetic energy of the grapefruit after it has fallen 2.0 m from its release point: a) calculate the difference between the gravitational potential energy at the top and the 2.0 m mark. Ob) calculate the total energy at the top and add it to the gravitational potential energy at the 2.0 m mark. c) calculate the kinetic energy at the top and double it. ) None of these options will give you the kinetic energy of the grapefruit after it has fallen 2.0 m. Oe) calculate the difference between the total energy at the top minus the gravitational potential energy at the 2.0 m mark.Question 8 (1 point) Listen The amount of work done when an 80.00 kg person jumps 1.000 m into the air in 0.5000 s is: O a) 292.0-1 O b) 40.00 J c) 784.0 J d) 1568 J Oel 160.0 J Question 9 (1 point) Listen A 2.0 kg grapefruit is tossed at a speed of 5.0 m/s from a roof that is 6.0 m above the ground. After the grapefruit has fallen 2.0 m from the top of the roof, what is its new gravitational potential energy? a) 78 J Ob) 98 J O c) 4.0 J O d) None of these options are correct O e) 39 J 804Question 20 (1 point) Listen In which case is positive work being done? a) An apple falls from a tree, Ob) Friction slows a puck sliding along the ice. c) A book sits on a shelf 2 m above the floor. O d) A skateboarder glides up an incline. Oe) None of the above.Question 6 (1 point) Listen The unit of work is the joule (J) which is equivalent to: O a) kgom/5 2 O b) kgom 3 /52 O c) kgom/s O d) watt 81 O el kgom 2 /5 2 Question 7 (1 point) Listen A 2.0 kg grapefruit is tossed at a speed of 5.0 m/s from a roof that is 6.0 m above the ground. What is the kinetic energy of the grapefruit as it is released (6.0 m level)? O a) 50 J O b) 25 J O c) None of these options are correct O d) 10 J O e) 12.5 J Question 8 (1 point) 804 A 956 OQuestion 3 (1 point) Listen A 5.00 kg sack of potatoes is raised to a height of 2.00 m and then thrown at a constant velocity of 2.00 m/s onto a truck. What is the initial kinetic energy of the potatoes? O a) 108 J O b) 103 J O c 98.0 J O d) 5.00 J O e) 10.0 J Question 4 (1 point) Listen Calculate the work done by planet X on its moon. Planet X applies a force o 5.6 x 1010 N on its moon and the moon is 4.0 x 108 km away from the plan and it continues to circle the planet in a circular orbit of circumference of 2. x 10' m. O a) 0.0 J Ob) - 2.2 * 1019 ) O c) - 1.4 x 1020 , O d) +2.2 * 1019 , O e ) +1.4 x 1020 ,Question 16 (1 point) Listen A 2.0 kg grapefruit is tossed at a speed of 5.0 m/s from a roof that is 6.0 m above the ground. What is the E of the grapefruit when it is 6.0 m off the ground? O al 30 J b) None of these options are correct O c) 1.2 x 102 J O d) 12 J O e) 1.4 x 102 JQuestion 13 (1 point) Listen A string hangs motionless over a frictionless pulley as shown in the diagram below. A 1.0 kg mass hangs on one side of the pulley and 2.5 kg mass hangs on the other side. Both masses are initially at rest with the 1.0 kg mass on the floor. The kinetic energy of the two masses just before the 2.5 kg mass hits the floor: O a) equal the difference between the gravitational potential energies before release and just before the 2.5 kg mass hits the floor. Ob) equals the potential energy of the 2.5 kg mass just before the release, divided by the total mass. O d) equal the sum of the gravitational potential energies before the release and just before the 2.5 kg mass hits the floor. Od) equals the potential energy of the 1.0 kg mass just before the 2.5 kg mass hits the floor. e) equals the potential energy of the 2.5 kg mass before release