Question
HELLO tutor please help me this question. MUST USE EXCEL to solve this question The manufacturer of a certain brand of cigarettes states that the
HELLO tutor please help me this question. MUST USE EXCEL to solve this question
The manufacturer of a certain brand of cigarettes states that the nicotine content in their cigarettes is 18.2mg with a standard deviation of 1.15mg. An independent testing agency examined a random sample cigarettes (sample below). At a 5% level of significance, is there evidence for the testing agency to conclude that the mean nicotine level to be higherthan the company states?
Cigarette Nicotine Level (mg) | ||||||||||||
19.51 | 17.34 | 19.58 | 18.31 | 18.98 | 19.02 | 18.63 | 18.4 | 18.32 | 17.74 | 18.82 | 17.92 | 17.77 |
18.54 | 17.93 | 17.01 | 17.23 | 19.25 | 17.09 | 17.32 | 17.97 | 19.29 | 18.77 | 19.34 | 18.57 | 17.33 |
19.29 | 17.8 | 17.12 | 17.74 | 17.3 | 19.45 | 18.76 | 18.81 | 17.78 | 17.21 | 17.49 | 18.9 | 17.73 |
19.42 | 19.25 | 18.63 | 17.76 | 19.16 | 18.36 | 19.6 | 17.19 | 17.63 | 18.83 | 18.34 | 18.06 | 17.44 |
17.82 | 17.51 | 18.17 | 19.3 | 18.14 | 17.11 | 18.74 | 19.22 | 18.55 | 18.92 | 19.19 | 19.17 | 18.05 |
18.52 | 17.72 | 19.02 | 18.21 | 18.97 | 17.17 | 18.61 | 18.43 | 18.44 | 19.12 | 19.04 | 18.87 | 18.13 |
18.14 | 19.09 | 19.1 | 18.47 | 18.31 | 17.42 | 19.17 | 19.56 | 18.43 | 18.13 | 18.42 | 17.38 | 17.98 |
18.22 | 19.49 | 17.9 | 18.17 | 18.61 | 17.82 | 19.55 | 18.91 | 19.39 | 17.73 | 18.51 | 17.54 | 19.08 |
19.4 | 18.46 | 18.13 | 17.92 | 17.27 | 18.54 | 19.34 | 18.05 | 17.26 | 17.59 | 19.47 | 18.1 | 18.14 |
19.1 | 18.42 | 17 | 17.17 | 19.53 | 17.93 | 17.9 | 18.62 | 17.53 | 18.19 | 17.53 | 17.59 | 19.36 |
17.62 | 17.73 | 17.85 | 18.58 | 18.21 | 18.85 | 18.1 | 17.35 | 18.62 | 19.02 | 17.87 | 18.76 | 18.1 |
18.48 | 18.07 | 18.62 | 18.16 | 19.16 | 18.56 | 18.35 | 18 | 17.86 | 17.39 | 19.49 | 19.37 | 17.41 |
19.03 | 19.28 | 17.17 | 18.58 | 17.54 | 17.77 | 17.78 | 18.4 | 17.36 | 17.09 | 18.46 | 18.43 | 18.65 |
17.1 | 17.48 | 17.74 | 17.34 | 17.08 | 17.8 | 18.04 | 18.68 | 17.52 | 19.59 | 19.21 | 17.65 | 18.49 |
19.13 | 18.31 | 17.26 | 17.33 | 19.45 | 18.62 | 19.46 | 19.22 | 18.06 | 17.69 | 18.55 | 19.2 | 17.47 |
18.22 | 19.19 | 18.96 | 18.71 | 17.56 | 19.6 | 17.4 | 19.24 | 19.16 | 17.04 | 17.65 | 17.9 | 17.57 |
19.36 | 19.18 | 17.91 | 18.8 | 17.47 | 18.61 | 17.17 | 19.05 | 17.55 | 19.1 | 18.56 | 17.95 | 18.86 |
18.45 | 18.24 | 19.57 | 17.1 | 18.03 | 18.09 | 19.34 | 19.51 | 18.93 | 18.5 | 19.08 | 18.7 | 18.58 |
18.31 | 19.6 | 18.09 | 17.26 | 17.43 | 18.08 | 18.28 | 19.39 | 17.79 | 18.66 | 18.53 | 18.95 | 17.67 |
18.19 | 18.66 | 19.17 | 18.5 | 18.35 | 19.13 | 19.48 | 19.11 | 17.84 | 18.83 | 17.51 | 18.26 | 18.91 |
17.74 | 17.1 | 18.47 | 17.75 | 17.01 | 17.81 | 19.28 | 18 | 18.85 | 17.65 | 17.68 | 19.34 | 17.58 |
BLANK #1: Is this a question involving mean or proportion? ***ANSWER "MEAN" OR "PROPORTION" Explain why
BLANK #2: Which type of distribution should be used to calculate the probability for this question? ***ANSWER "NORMAL", "T", OR "BINOMIAL" explain
BLANK #3: Which of the following options are the appropriate hypotheses for this question:
A) H0: = 18.2mg H1: > 18.2mg
B) H0: = 18.2mg H1: < 18.2mg
C) H0: = 18.2mg H1: 18.2mg
D) H0: p = 18.2mg H1: p > 18.2mg
E) H0: p = 18.2mg H1: p < 18.2mg
F) H0: p = 18.2mg H1: p 18.2mg
BLANK #4: What is the p-value of this sample? ***ANSWER TO 4 DECIMALS, MUST USE EXCEL TO SOLVE
BLANK#5: Based on this sample,at a 5% level of significance, is there evidence for the testing agency to conclude that the mean nicotine level to be higherthan the company states? ***ANSWER "YES" OR "NO" and why
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