Hello tutors, can I please get your assistance with the following problem? thank you very much!

At any given time t > 0 (measured in seconds), the rate at which an eagle's altitude is changing is t(lnt)5(measured in feet per second). For example, (21)(ln21)50.3200 and (9)(ln9)55.6902, which means that at t =21 seconds, the eagle's altitude is decreasing at a rate of around 0.3200 feet per second, and at t = 9 seconds, the eagle's altitude is increasing at a rate of around 5.6902 feet per second. For each question below, if it cannot be solved can you please explain why there is not enough information to answer it.

(a) At what time is the eagle lowest? (b) How high is the eagle at t = e² seconds? (c) How much higher is the eagle at t = e² seconds than he was at t = e seconds?