Hello tutors, I badly need help to solve these problems. Thank you so much

Example 33 The following set of raw data shows the lengths, in millimeters, measured to the nearest mm, of 40 leaves taken from plants of a certain species. This is the table of frequency distribution. Lengths (mm) Frequency ( f, ) 25 - 29 2 30 - 34 4 35 - 39 7 40 -44 10 45 - 49 8 50 - 54 6 55 - 59 3 Solution The modal class is 40 - 44, so LbM. = . ..... a= . ..... -......= ...... and b= ......-...... =. . .... Thus Mo = LbMo + a -.C atb Mo = ......+ . . .... ...... . . ....+ .. .... Mo = ......+ ...... MO = . . . . ..... By histogram CE = . . .. .. - .. .. .. ...... DF = .. . ...-.. AP : PB = CE : DF 10 AP : PB = ...... . .. ..... P A B AP : AB = ...... : (.... + ....) Frequency AP : ...... = ...... . ....... AP - ....X ...... . . . . . . 4 AP= ....... .. Mo = 39.5 + AP 24.5 29.5 34.5 39.5 44.5 49.5 54.5 59.5 Mo = 39.5 + ...... =...... Lengths (mm) Example 34